Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
A | 1200 | 102 | 3 | 34.0000 |
O | 1365 | 121 | 4 | 30.2500 |
Em | 259 | 23 | 1 | 23.0000 |
mas | 453 | 21 | 1 | 21.0000 |
Na | 185 | 18 | 1 | 18.0000 |
Os | 269 | 13 | 1 | 13.0000 |
Para | 179 | 13 | 1 | 13.0000 |
E | 150 | 11 | 1 | 11.0000 |
Por | 105 | 9 | 1 | 9.0000 |
No | 239 | 15 | 2 | 7.5000 |
Isso | 66 | 7 | 1 | 7.0000 |
Já | 89 | 7 | 1 | 7.0000 |
É | 192 | 14 | 2 | 7.0000 |
As | 191 | 13 | 2 | 6.5000 |
Com | 118 | 6 | 1 | 6.0000 |
Ele | 145 | 12 | 2 | 6.0000 |
quanto | 61 | 5 | 1 | 5.0000 |
desde | 139 | 10 | 2 | 5.0000 |
Não | 145 | 10 | 2 | 5.0000 |
devido | 61 | 5 | 1 | 5.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
R | 223 | 1 | 11 | 0.0909 |
sido | 78 | 1 | 10 | 0.1000 |
outro | 75 | 1 | 7 | 0.1429 |
anos | 371 | 7 | 49 | 0.1429 |
projeto | 74 | 1 | 6 | 0.1667 |
próprio | 47 | 1 | 6 | 0.1667 |
redes | 72 | 1 | 6 | 0.1667 |
poder | 70 | 1 | 6 | 0.1667 |
jovem | 36 | 1 | 6 | 0.1667 |
sendo | 138 | 1 | 6 | 0.1667 |
nosso | 63 | 1 | 5 | 0.2000 |
sociedade | 32 | 1 | 5 | 0.2000 |
série | 48 | 1 | 5 | 0.2000 |
lista | 33 | 1 | 5 | 0.2000 |
hospital | 45 | 1 | 5 | 0.2000 |
bom | 41 | 1 | 5 | 0.2000 |
falta | 67 | 1 | 5 | 0.2000 |
campanha | 42 | 1 | 5 | 0.2000 |
queda | 38 | 1 | 5 | 0.2000 |
Agência | 21 | 1 | 5 | 0.2000 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II